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Water Density and Boiling Point

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  • Pages: 3
  • Word count: 608
  • Category: Water

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Part A
1. Diameter of the test tube.1cm
2. Length of test tube.11.5cm
3. Volume of the test tube.9.032
4. Mass of the empty test tube.10.35g
5. Mass of the filled test tube.29.89g
6. Mass of liquid in test tube.19.54
7. Temperature of the water.22ºc

Part B
Aluminum Sinker
1. Mass of object.6.87g49.44g
2. Volume of the water in the graduated
Cylinder after the addition of the object.17.5mL19mL
3. Volume of the object due to displacement2.5mL4mL
4. Density of object.2.74812.36
5. Calculated mass of the sinker in ounces1.74g

Part C
1. Length of the foil8.5cm
2. Width of the foil8.5cm
3. Mass of the foil.60g
4. Volume of the foil.222
5. Thickness of the foil.0031

Part D
1. Boiling point of the ethanol65ºc
Part E
1. T¹ initial temperature125ºc
2. T² final temperature155ºc

Post lab questions:
1. Based on my temperature value and my lab measurements, I calculated that the water density would be 2.16 (g/mL). This calculation of density does not match up with the density in the table provided. The table calculations would give the water with 22ºc a density of 0.99770. My calculation or lab measurements must be wrong because at 4ºc, water has a density at 1. The colder the water, the higher the density. 2. For the aluminum, I got 2.50 g/mL . The discrepancies may be that the literature value measurements measure at a different gram or mL, also because the aluminum may not has been torn off evenly. Although the measure 2.50 g/mL as a density in my calculations was very close to the literature value of density of 2.70 g/mL, there is only few explanations why the calculations would be the same. 3. For the lead, I got 12.36 g/mL. The discrepancies may be that the measurement in my lab were not accurate. Or that when I placed the lead into the graduated cylinder, the water shot out of it, resulting in a false and near perfect reading.

4. If the miners nugget has a mass of 16.5 and displacement of 3.3 mL of water, the calculations for g/mL would give the nugget a density of 5. Which when he compares that to the density of g/mL, gold comes out to be 18.9. This result shows that the nugget the miner found is infact not gold, but “fools gold”. 5. When ordering the following into the appropriate order from lightest to heaviest, 5 lb bad of potatoes, 1.65 kg cabbage, and 2500 g of sugar, you must convert the measurements into the same component. The bag of potatoes converts from 5 lb to 2240g, which makes the bag of potatoes lighter than the sugar. And already being that the bag of cabbage is in kg making that lighter than all of the measurements because kg is lighter and small than lb and g. the order is the following, 1. Cabbage 2. Potatoes 3. Sugar 6. The metal indium melts at 156ºc and the boiling point of cyclohexane is 321ºF. If Indium’s temperature is converted into Fahrenheit, that would give it a melting point of 313ºF.

Since cyclohexane’s boiling point is a higher temperature of indium, that would make the indium melt before the cyclohexane reached its boiling point. And when cyclohexane was at its boiling point, the indium would have been melting for the past 10 temperatures before cyclohexane. 7. The metric system is more accurate than the English system because the metric measures by 10s which gives the metric an even and whole measurement. Also the metric is known universal so everyone would know how the object in question is being measured. That gives the person measuring, an easier way to calculate so that the result of his calculations would be more accurate and precise.

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