We use cookies to give you the best experience possible. By continuing weâ€™ll assume youâ€™re on board with our cookie policy

# Solving Proportions

The whole doc is available only for registered users

A limited time offer! Get a custom sample essay written according to your requirements urgent 3h delivery guaranteed

Order Now

This week I learned about solving proportions. Rightfully so, on this assignment I have to prove or show what Iâ€™ve learned and retained by solving two problems. In this essay I will attempt to solve two problems from our textbook, the first one is problem 56 located on page 437 and the second one is problem 10 located on page 444 of our Elementary and Intermediate Algebra textbook. During this process I will incorporate the four math vocabulary words required, which are extraneous, proportion, cross multiply, and extreme-means which will be in bold. Problem number 56 located on page 437 states and asks the following about bear population. â€śTo estimate the size of the bear population on the Keweenaw Peninsula, conservationist captured, tagged, and released 50 bears.

One year later, random sample of 100 bears included only 2 tagged bears. What is the conservationistâ€™s estimate of the size of the bear population?â€ť (Dogupolski, 2012). Since this is a ratio equation I will use b for the variable, b equaling the bear population which is what we need to find. The first thing I did was to set up the two ratios, place the b for the variable which equals the bear population in this proportion. Then I cross multiply the extreme-means property as shown below.
2*b=100*50
2b=5000

Because we want to solve for b I had to isolate it by dividing both sides of the proportion by 2. This gave me the answer of 2500. Keep in mind that since the denominator was not zero this equation does not merit to be considers extraneous. 2b=2500

This is the estimated size of the bear population according toÂ conservationists. This problem is a little more complicated for me so here goes nothing. For this second problem I will solve for y. I will do this by first cross multiplying the extreme-means since this is a single fraction on both sides as you can see below.

The problem below is a proportion.
y-1 =-3
x+3 4
(y-1)*4=(x+3)-(-3)
I then cross multiply the x and y which are the extreme-means 4y-4=-3x-9 and then distribute the 4 and the -3. 4y=-3x-9+4 add 4 to both sides
4y=-3x-5 divide both sides by 4
y= -3 x-5 both of these fractions are in parentheses the x and â€“ are outside the ( ) 4, 4 The linear equation in the form of y=mx+b with the slope of -3, 4

I hope that Iâ€™ve covered everything in my essay and really looking forward for some great feedback.

References
Dugopolski, M. (2012). Elementary and Intermediate Algebra (4th ed.). New York, NY: McGraw-Hill Publishing.

##### Related Topics

We can write a custom essay

Order an essay
300+
Materials Daily
100,000+ Subjects
2000+ Topics
Free Plagiarism
Checker
All Materials
are Cataloged Well

Sorry, but copying text is forbidden on this website. If you need this or any other sample, we can send it to you via email.

Sorry, but only registered users have full access

immediately?

Thank You A Lot!

Emma Taylor

online

Hi there!
Would you like to get such a paper?
How about getting a customized one?

Can't find What you were Looking for?